Two extra tricks need to be kept in mind when dealing with exponential functions.
Example 5 |
|
4xe2x 8ex |
Strategy |
4xe2x and 8ex |
Consider each product separately,
but watch out for sums which may be in common |
4 and 8 have a HCF of 4 |
Find the highest common factor
of the numeric parts of the product expressions. |
x is in only one term |
Find the common factor for
factors involving a variable. |
Since e2x = (ex)2
e2x and ex have ex in common |
Find the common factor for factors which involve exponential factors. |
Hence 4ex is the largest common
factor. |
|
4xe2x 8ex
= 4ex(xex)
+ 4ex(2)
= 4ex(xex
+ 2) |
Put the parts together. |