Chain Rule Exercise Answers

  1. y = e2x−1

    y = eu and u = 2x − 1 so dy by du= eu and du by dx= 2

    dy by dx = dy by dutimesdu by dx= eutimes2 = 2e2x−1

  2. y = ln (5x −3)

    y = ln u and u = 5x − 3 so dy by du= 1 over uand du by dx= 5

    dy by dx = dy by dutimesdu by dx= 1 over utimes5 =5 over u = 5 over (5x minus 3)

  3. y = (4 − x)7

    y = u7 and u = 4 − x so dy by du= 7u6 and du by dx= −1

    dy by dx = dy by dutimesdu by dx= 7u6 times(−1) = −7u6 = −7(4 − x)6

  4. y = sin (x + 4)

    y = sin u and u = x + 4 so dy by du= cos u and du by dx= 1

    dy by dx = dy by dutimesdu by dx= (cos u)times1 = cos u = cos (x + 4)

  5. y = ecos x

    y = eu and u = cos x so dy by du= eu and du by dx= −sin x

    dy by dx = dy by dutimesdu by dx= eutimes( −sin x) = (−sin x)ecos x

  6. y = ln (5x3 − 12)

    y = ln u and u = 5x3 − 12 so dy by du= 1 over u and du by dx= 15x2

    dy by dx = dy by dutimesdu by dx= 1 over u times15x2 =15 x squared over u= 15 x squared divided by 5 x cubed minus 12

  7. y = cos (x4)

    y = cos u and u = x4 so dy by du= −sin u and du by dx= 4x3

    dy by dx = dy by dutimesdu by dx= ( −sin u) times4x3 = −4x3sin (x4)

  8. y = cos4 x

    y = u4 and u = cos x so dy by du= 4u3 and du by dx= −sin x

    dy by dx = dy by dutimesdu by dx= 4u3 times( −sin x) = (−4sin x)u3 = (−4sin x)cos3x

  9. y = ln (3x + 1 )

    y = ln u and u = 3x + 1 so dy by du= 1 over u and du by dx= 3

    dy by dx = dy by dutimesdu by dx= 1 over utimes3 = 3 over u= 3 over (3x+1)

  10. y = sin2x

    y = u2 and u = sin x so dy by du= 2u and du by dx= cos x

    dy by dx = dy by dutimesdu by dx= 2u timescos x =2(sin x)(cos x)

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